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in 100m race, A beats B by 10m and B beats C by 20m.By how
much distance A beats C.
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Answer Posted / avcs
The answer is 28m.
Let A completes race in t1 secs.
velocity(A)=100/t1 ; Velocity (B)=90/t1;
B completes race in t2 secs
Velocity(B)=100/t2; Velocity (C)=80/t2;
now 90/t1=100/t2 => t2=10*(t1)/9;
Velocity (C) = 80 * 9/10*(t1)= 72/t1;
So A defeats C by 28 meters.
| Is This Answer Correct ? | 46 Yes | 7 No |
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