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main()
{
int y=10;
if(y++>9 && y++!=10 && y++>10)
{
printf("%d",y);
else
printf("%d",y);
}
}

Answers were Sorted based on User's Feedback



main() { int y=10; if(y++>9 && y++!=10 && y++>10) { printf("..

Answer / jane

13

Is This Answer Correct ?    11 Yes 2 No

main() { int y=10; if(y++>9 && y++!=10 && y++>10) { printf("..

Answer / yash golwara

answer will be 13 but we need to first need to edit the code it has some errors
so could be this
#include<stdio.h>
#include<conio.h>
main()
{
int y=10;
if(y++>9 && y++!=10 && y++>10)
{
printf("%d",y);
}
else
printf("%d",y);
}

so now it will give answer 13 in each process it svalues increases and three process so it will increase to 13

Is This Answer Correct ?    4 Yes 2 No

main() { int y=10; if(y++>9 && y++!=10 && y++>10) { printf("..

Answer / shruthi

12

Is This Answer Correct ?    2 Yes 2 No

main() { int y=10; if(y++>9 && y++!=10 && y++>10) { printf("..

Answer / nagendra kumar

10

Is This Answer Correct ?    3 Yes 7 No

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