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Cost of an item is x. It's value increases by p% and
decreases by p% Now the new value is 1 rupee, what is the
actual value ?

Question Posted / nazia banu

Answers were Sorted based on User's Feedback



Cost of an item is x. It's value increases by p% and decreases by p% Now the new value is 1 r..

Answer / v venu gopal

original cost is 100^2 / (100^2 - p^2) Rs

Is This Answer Correct ?    21 Yes 5 No

Cost of an item is x. It's value increases by p% and decreases by p% Now the new value is 1 r..

Answer / phaniram

Let the item cost be I then,

Item cost by increasing p% will be:
I(100+p)/100

Item Cost by decreasing p% will be:
I(100+p)(100-p)/100*100

But the above is equal to 1.

So,

I(100^2-p^2)/100^2 = 1 => I = 100^2/(100^2 - p^2).

Is This Answer Correct ?    24 Yes 9 No

Cost of an item is x. It's value increases by p% and decreases by p% Now the new value is 1 r..

Answer / sekhar

it depends on p value

if any item is increased and decresed by p percent actually
the value of item is decreased by 0.P^2%
so 100%-.p^2%=1rupee
100%=x



x=1oo*1/(100-.p^2)

Is This Answer Correct ?    7 Yes 6 No

Cost of an item is x. It's value increases by p% and decreases by p% Now the new value is 1 r..

Answer / chandradukpa

1=0
0=1
So, 1+1=0.

Is This Answer Correct ?    2 Yes 1 No

Cost of an item is x. It's value increases by p% and decreases by p% Now the new value is 1 r..

Answer / kumar n

please given me the correct answer for this question.

Is This Answer Correct ?    3 Yes 3 No

Cost of an item is x. It's value increases by p% and decreases by p% Now the new value is 1 r..

Answer / sandeep

consider '1' rupee as 100 and p=20
now it is increased by 20% then the cost is 120
and decreased by 20% now the cost is 96
since it is 1 rupee we get 0.96 ps

Is This Answer Correct ?    2 Yes 9 No

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