#include <iostream> using namespace std; int main() { int a = 2; int c

#include <iostream>
using namespace std;
int main() {
int a = 2;
int c[5][5];
for (int x=0;x<5;x++) {
for (int y=0;y<5;y++) {
c[x][y] = x*y;
}
}
cout << c[a][c[1][4]];
}

Question Posted / sandeep kumar gupta

2 Answers
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#include <iostream> using namespace std; int main() { int a = 2; int c[5][5]; for (int x=..

Answer / bhavana

c[2][4]=8

Is This Answer Correct ?

12 Yes

0 No

#include <iostream> using namespace std; int main() { int a = 2; int c[5][5]; for (int x=..

Answer / girish

The answer of this program is very easy.
every time the arry indices are multiplication is done.
Then a is 2 this is right and the logic is in second index value is in square brackets[].
It calculate the second index value and it gives 1*4=4.
And the final answer is
a=2 and c[1][4] =4
then
c[2]4] is 8
Thank you

Is This Answer Correct ?

9 Yes

1 No

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