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How to find the digits truncation when assigning the
interger variable to the character variables.
like int i=500; char x = i : here we have truncation. how to
find this.
another ex: i =100; char x=i. here we do not have
truncation.
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Answer / ashu
when i=500 in int which means it is not going beyond the limit of integer range in memory but when x=i which means we are assigning value of i to x.. that is now x becomes 500 whose data type is "char" and range is only -128 to 127 in signed & 0 to 255 in unsigned.. i.e. it is crossing the range.. there we find truncation here
where as in 2nd ex: i=100 which then x=i in char datatype that is char x variable is assigned with i=100 which is not byond range of char data type..therefor no truncation in this example we can find.
| Is This Answer Correct ? | 3 Yes | 1 No |
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