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number 2 plssssss help !!....using array.. turbo c..

create a program that will accept a number and determine if
it is a happy number or an unhappy number..

example:

enter a number : 7



7*7=49

then 4 and 9

4*4 and 9*9== 16 + 18 gives you 97

then 9 and 7

9*9 and 7*7 == 81 + 49 gives you 130

then 1 and 3

1*1 and 3*3 == 1 + 9 gives you 10

1*1 gives you 1



sample output:



7= 49= 16+81= 97= 81+49=130 =1+9=10 =1


"7 is a happy number"





. if the last number is 2 then the number being inputed is
not a happy number.

Answers were Sorted based on User's Feedback



number 2 plssssss help !!....using array.. turbo c.. create a program that will accept a number a..

Answer / swapnil chhajer

#include<stdio.h>
#include<stdlib.h>
#include<string.h>

int happyNumber(int n)
{
char temp[10];
itoa(n,temp,10);
int len=strlen(temp);
int ret,sum=0,i;

if(n==1)
return 1;
else if(n==4)
return 0;
else
{
for(i=0;i<len;i++)
sum += (temp[i]-48)*(temp[i]-48);
ret = happyNumber(sum);
}

return ret;
}


int main()
{
int n;
printf("Enter the number : ");
scanf("%d",&n);
if(happyNumber(n) == 1)
printf("\n\n%d is a HAPPY NUMBER",n);
else
printf("\n\n%d is NOT A HAPPY NUMBER",n);

fflush(stdin);
getchar();
return 0;
}

Is This Answer Correct ?    6 Yes 3 No

number 2 plssssss help !!....using array.. turbo c.. create a program that will accept a number a..

Answer / y hussain reddy

void main()
{
int n;
int f(int);
printf("nter number");
scanf("%d",&n);
while(n>9)
{
n=f(n*n);
}
if(n==1)
printf("%d is happy number",n);
else
printf("%d is unhappy number",n);
}
int f(int n)
{
int s=0;
while(n)
{
s+=(int)pow(n%10);
n=n/10;
}
return s;
}

Is This Answer Correct ?    5 Yes 4 No

number 2 plssssss help !!....using array.. turbo c.. create a program that will accept a number a..

Answer / wqw

29

Is This Answer Correct ?    3 Yes 3 No

Post New Answer

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