number 2 plssssss help !!....using array.. turbo c..
create a program that will accept a number and determine if
it is a happy number or an unhappy number..
example:
enter a number : 7
7*7=49
then 4 and 9
4*4 and 9*9== 16 + 18 gives you 97
then 9 and 7
9*9 and 7*7 == 81 + 49 gives you 130
then 1 and 3
1*1 and 3*3 == 1 + 9 gives you 10
1*1 gives you 1
sample output:
7= 49= 16+81= 97= 81+49=130 =1+9=10 =1
"7 is a happy number"
. if the last number is 2 then the number being inputed is
not a happy number.
- 3 Answers
- 6810 Views
- I also Faced
- E-Mail Answers
Answers were Sorted based on User's Feedback
Answer / swapnil chhajer
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
int happyNumber(int n)
{
char temp[10];
itoa(n,temp,10);
int len=strlen(temp);
int ret,sum=0,i;
if(n==1)
return 1;
else if(n==4)
return 0;
else
{
for(i=0;i<len;i++)
sum += (temp[i]-48)*(temp[i]-48);
ret = happyNumber(sum);
}
return ret;
}
int main()
{
int n;
printf("Enter the number : ");
scanf("%d",&n);
if(happyNumber(n) == 1)
printf("\n\n%d is a HAPPY NUMBER",n);
else
printf("\n\n%d is NOT A HAPPY NUMBER",n);
fflush(stdin);
getchar();
return 0;
}
| Is This Answer Correct ? | 6 Yes | 3 No |
Answer / y hussain reddy
void main()
{
int n;
int f(int);
printf("nter number");
scanf("%d",&n);
while(n>9)
{
n=f(n*n);
}
if(n==1)
printf("%d is happy number",n);
else
printf("%d is unhappy number",n);
}
int f(int n)
{
int s=0;
while(n)
{
s+=(int)pow(n%10);
n=n/10;
}
return s;
}
| Is This Answer Correct ? | 5 Yes | 4 No |
Write a main() program that calls this function at least 10 times. Try implementing this function in two different ways. First, use an external variable to store the count. Second, use a local variable. Which is more appropriate?
why use "return" statement a) on executing the return statement it immediately transfers the control back to the calling program b) it returns the value present in the parentheses return, to the calling program c) a & b d) none of the above
What are linked lists in c?
What is preprocessor with example?
What is wrong with this initialization?
#include<stdio.h> void main() { int a=5,b=6,c; int x=(a<b)+7; int y=(x==7)*9; int z=(c=x+y)*2; printf("%h %h %h",x,y,z); } What is the output? Explain it.
How to create struct variables?
Every time i run a c-code in editor, getting some runtime error and editor is disposing, even after reinstalling the software what may be the problem?
Explain what does the format %10.2 mean when included in a printf statement?
What oops means?
What are structure members?
Write c-code for 5+55+555+5555+55555+555555+5555555. Output will be it's answer...
C 
