Interested to Buy Any Domain ? << Click Here >> for more details...
If you had the following code: int x = 23; int *y; y = &x;
The instruction y++; does what?
- 2 Answers
- 4710 Views
- I also Faced
- E-Mail Answers
Answers were Sorted based on User's Feedback
Answer / naresh kumar
here Y is integer pointer which is storing address of x.
suppose we assume address of X is 65524. this value will stored in pointer variable Y. int variable is capable of storing 2 bytes of memory. If increment or decrement variable Y, It points to next memory location, i.e 65526.
that means y=65524
y++
65526
y++
65528
this will keep on increasing by 2 bytes.
| Is This Answer Correct ? | 4 Yes | 1 No |
Answer / anu
Then y will point to next memory location.
If we are using (*y)++ will increment value to 24.
| Is This Answer Correct ? | 4 Yes | 5 No |
What are the comments in c++?
What is the Difference between "C structure" and "C++ structure"?
What is the difference between equal to (==) and assignment operator (=)?
Why c++ is created?
Write about the local class and mention its use?
Can you think of a situation where your program would crash without reaching the breakball, which you set at the beginning of main()?
What is a rooted hierarchy?
Write about a nested class and mention its use?
What is size of empty class object
What is enum class in c++?
What is the difference between map and hashmap in c++?
Explain what is class definition in c++ ?
STL 
