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If you had the following code: int x = 23; int *y; y = &x;
The instruction y++; does what?
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Answer / naresh kumar
here Y is integer pointer which is storing address of x.
suppose we assume address of X is 65524. this value will stored in pointer variable Y. int variable is capable of storing 2 bytes of memory. If increment or decrement variable Y, It points to next memory location, i.e 65526.
that means y=65524
y++
65526
y++
65528
this will keep on increasing by 2 bytes.
| Is This Answer Correct ? | 4 Yes | 1 No |
Answer / anu
Then y will point to next memory location.
If we are using (*y)++ will increment value to 24.
| Is This Answer Correct ? | 4 Yes | 5 No |
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