three taps a, b, c, together can fill an empty cistern in
10 minutes. the tap a alone can fill it in 30 minutesand
the tap b alone 40 minutes. how long will the tap c alone
take to fill it
Answers were Sorted based on User's Feedback
Answer / imran
answer is 24
let the volume of bucket be v
let the speed of water flowing through a be v1,b be v2 ,c be v3
(v1+v2+v3)10=v
30*v1=v
40*v2=v
x*v3=v
{(v/30)+(v/40)+(v/x)} *10=v
by solving we get x=24
| Is This Answer Correct ? | 14 Yes | 2 No |
Answer / parthi
24.take l.c.m. for three time is given to fill the tank and
empty the tank(cistron),take ratio of all and subract fill
ratio from empty ratio then divide common lcm factor from
recquired ans we get ans....................
| Is This Answer Correct ? | 3 Yes | 2 No |
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