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Q2. Pipe A takes 16 min to fill a tank. Pipes B and C, whose
cross-sectional circumferences are in the ratio 2:3, fill
another tank twice as big as the first. If A has a
cross-sectional circumference that is one-third of C, how
long will it take for B and C to fill the second tank?
(Assume the rate at which water flows through a unit
cross-sectional area is same for all the three pipes.)
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Answer / manish thakur
Circumference units -> C = 1; B = 2/3; A = 1/3
Pipe cross sectional area units -> C = 1; B = 4/9; A = 1/9
Time = volume/ flow rate
Flow rate = constant x cross section area
Using the above, we can derive the time taken by B and C to
fill the tank, which twice the size of what A fills.
Solving, we get
Desired answer = 32/13
| Is This Answer Correct ? | 84 Yes | 13 No |
Answer / vishal
hello guys i have some doubt lets solve it this way
x , y ,z be the spped of water coming out of A , B ,C(in ltr /min ) repctivly , V be the first tank volume then 2V will be the secont tank volume now
16 x = V ( pipe A takes 16 min to fill tank )
now the cross sections ration gives us radius ratio whcih gives us area ratio ,
hence y/z = 9/4 also x/z = 9/1 now if the two pipes fill secont tank in t time then
(y+z)*t = 2V put ol the values in terms of x , x gets cancel and answer is 32* 36 /13 what is the mistake i have done plzz tell me
| Is This Answer Correct ? | 1 Yes | 6 No |
Answer / prakash
A takes 16 min for frist tank.. B and C circumfrence is 2:3... And A circum is one third of C so A is 1/3... Now
we have to fill twice the frist tank so A takes 32 min to fill.. B and C fills 5 time of A then ... So 32/5 is 6.4 min...
| Is This Answer Correct ? | 8 Yes | 15 No |
Answer / naveen
the pipe B and c takes 32 minutes to fill the second tank
| Is This Answer Correct ? | 6 Yes | 15 No |
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