What is the output of below code?
main()
{
static in a=5;
printf("%3d",a--);
if(a)
main();
}
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54321
here main() is called again in main function
this leads to recursion....
the function is called until a become 0.
value is retained as static key word is used.
not much clear about usage of "%3d"
| Is This Answer Correct ? | 10 Yes | 1 No |
Answer / amol subhash kumbhar
Output is:- 5 4 3 2 1 (This Manner)
In main()
Static is the Preserves Keyword Used to Statically allocate
the memory allocation
%3d means the 3 space are allocate in the output like as 5
4 3 2 1
main() :- main function called in main function means
recursion is applied
| Is This Answer Correct ? | 5 Yes | 0 No |
Answer / pratik panchal
output:5 4 3 2 1
static int store the value of variable for once and
periodically changes its value as the variable value changes
and a-- is done so the assigned value on the next line will
automatically overwrite the value of a.
%3d means print 5 then 2 spaces and 4 and so on..,.main is
called until if statement gets false..if(5) is a true
condition.
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / moloy mondal
the output will be infinite no. of 5s ..bcoz integer a is
static its value wont b changed ever..
| Is This Answer Correct ? | 2 Yes | 4 No |
#include<stdio.h> #include<conio.h> void main() {clrscr(); char another='y'; int num; for(;another=='y';) { printf("Enter a number"); scanf("%d",&num); printf("squre of %d is %d",num,num*num); printf("\nwant to enter another number y/n"); scanf("%c",&another); } getch(); } the above code runs only one time.on entering 'y' the screen disappeares.what can i do?
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