Answer / govindkrishna

#include<stdio.h>
#include<conio.h>
main()
{
char ch;
printf("enter any charecter %c /n");
scanf("%c ",&ch);
printf("the ACSCII value is %d= /n",ch);
}

Answer / priya

Can any one tell me the answer....
if any one knows the answer pls mail the answer at this id
plsss
priya_del06@yahoo.com

Answer / rukmanee

#include<stdio.h>
#include<conio.h>
void main()
{
char ch;
clrscr();
printf("\n enter a character :");
scanf("%c",&ch);
printf("the corresponding ascii value of the given
character is %d",ch);
getch();
}

Answer / pansare sandeep

#include <iostream.h>
#include<conio.h>
void main()
{
char c;
int d;
clrscr();
cout<<"Enter any key"<<endl;
cin>>c;
d=c;
cout<<"Corresponding ascii is "<<d;
getch();
}

Answer / sanjay malik

#include<stdio.h>
main()
{
char ch;
printf("ENTER A CHARACTER: ");
scanf("%c",&ch);
printf("THE ASCII CODE IS %d",ch);}

Answer / priya.m

#include<iostream.h>
#include<conio.h>
void main()
char c;
int a;
clrscr();
cout<<"enter any word"<<photo;
cin>>c;
a=c;
cout<"corresponding ASCII is"<<a;
getch();
}

Answer / pawankumar

#include<stdio.h>
#include<conio.h>
void main()
{
clrscr();
int x;
char y;
printf("enter the number");
scanf("%d",&x);
printf("enter the char");
scanf(" %c",&y);
if(sizeof(x)==4)
{
printf("the equivalent char for given
integer is %c ",x);
}
if(sizeof(y)==1)
{
printf("the equivalent integer for given
char is %d ",y);
}

}

Answer / nigus alene

#2 is correct.

Answer / ashokan m

#include<stdio.h>
#include<conio.h>
main()
{
clrscr();
int x;
char y;
printf("enter the number");
scanf("%d",&x);
printf("enter the char");
scanf("%c",&y);
if(sizeof(x)==2))
{
printf("the equivalent char for given integer is %c ",x);
}
elseif(sizeof(y)==1)
printf("the equivalent integer for given char is %d ",y);
getch();
}

b) 4 c) 6 d) 7 32. Any C program a) must contain at least one function b) need not contain ant function c) needs input data d) none of the above 33. Using goto inside for loop is equivalent to using a) continue b) break c) return d)none of the above 34. The program fragment int a=5, b=2; printf(“%d”,a+++++b); a) prints 7 b)prints 8 c) prints 9 d)none of the above 35. printf(“ab” , “cd”,”ef”); prints a) ab abcdef c) abcdef, followed by garbage value d) none of the above 36. Consider the following program segment. i=6720; j=4; while((i%j)==0) { i=i/j; j=j+1; } On termination j will have the value a) 4 b) 8 c) 9 d) 6720

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