A man travels from A to B at 4 mph over a certain journey
and returns over the same route to A, at 5 mph. What is his
average speed for the journey?
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Answer / suresh
let, x be man travel from A to B and
Y be man travel from B to A then
Average speed is (2XY)/(X+Y)
therefore ans = (2*4*5)/(4+5)
= 4.44mph
| Is This Answer Correct ? | 93 Yes | 4 No |
Answer / david
Imagine that the distance from A to B is 20 miles (lowest
common denominator of 4 and 5)
That means on the way there it took him 5 hours (20/4)
On the way back it took him 4 hours (20/5)
So in total it took him 9 hours (5+4) to travel 40 miles (20
miles each way).
So 40/9 = 4.444mph
| Is This Answer Correct ? | 26 Yes | 1 No |
Answer / guest
avg speed =2xy/x+y
avg speed=2*4*5/(4+5)
=40/9=4.444mph
| Is This Answer Correct ? | 13 Yes | 0 No |
Answer / kishore jangid
Average Speed:
(2xy)/(x+y)
Therefore
=(2*4*5)/(4+5)
=(40)/(9)
=4.4444...
| Is This Answer Correct ? | 6 Yes | 0 No |
Answer / raviraj mishra
FORMULA FOR AVG. SPEED WHEN DISTANCE TRAVELLED IN TWO
INTERVALS IS SAME , IS GIVEN BY = 2*A*B/A+B
, A=4mph & B=5MPH SO ANSWER=4.44mph
| Is This Answer Correct ? | 2 Yes | 0 No |
Answer / bala
man A to B = 4mph
man B to A = 5mph
(4/100=4%, 5/100=5%)
average speed =4mph+5mph/200*100
=4.5mph.
| Is This Answer Correct ? | 2 Yes | 1 No |
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