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#include<std.h>
int main()
{
char *str[]={"Frogs","Do","Not","Die","They","Croak!"};
printf("%d %d\n",sizeof(str),strlen(str));
...return 0;
}
what will the output of the above program?
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hi dear my name is Amit.
firtly i want to ask that you have used std.h. header
file.can u tell me about this one becuouse i am using
stdio.h header file instead of it.it can make an error if
it is not header file.second thing is that you have used
function strln() which is the function of string.h. to use
this function we have to this header file.it will produced
error with out this header file.
#include<stdio.h>
#include<conio.h>
#include<string.h>
main()
{
char *str[]={"Frogs","Do","Not","Die","They","Croak!"};
printf("%d %d\n",sizeof(str),strlen(str));
getch();
}
the out put will be 12 and 1....
| Is This Answer Correct ? | 3 Yes | 1 No |
Answer / janava
In this it generate an error because declaration the array
as char but read the variable as integer.
| Is This Answer Correct ? | 7 Yes | 6 No |
Answer / s.ramakrishna
thw output becomes 6 6
why because the character pointer stores their values and
that will be printed
| Is This Answer Correct ? | 4 Yes | 3 No |
Answer / naresh lingampally
will be a error since ..
syn: *x will be a pointer and it would always be a digit .
so no variable address can be a character ...
MAKES SENSE ?
| Is This Answer Correct ? | 0 Yes | 1 No |
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| Is This Answer Correct ? | 0 Yes | 3 No |
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C 
