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In the reading room of a library, there are23 reading spots.
Each reading spot consists of a round table with 9 chairs
placed around it. There are some readers such that in each
occupied reading spot there are different numbers of
readers. If in all there are 36 readers, how many reading
spots do not have even a single reader?
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Answer / d乇乇pansh
AS ,There are some readers such that in each
occupied reading spot there are different numbers of
readers.
1+2+3+4+5+6+7+8= 36 readers
so ,8 spots have different readers.
remainings are 23-8= 15.
15 spots are empty.
| Is This Answer Correct ? | 154 Yes | 20 No |
Answer / mayank katiyar
by default we have to consider max tables should remain empty.
so 1+2+3+4+5+6+7+8=36readers
therefore
23-8seats=15.
| Is This Answer Correct ? | 23 Yes | 6 No |
Answer / hari
he just said that in each different spot there are different
number of readers. So there will be many possibilities...
It is same as number of ways in which you can make a sum of
9 using only digits from 1 to 9 each at most once...
Consider
1+2+3+6+7+8+9 = 36
In this case answer is: 23-7 = 16
but different answers are possible depending on case u choose
| Is This Answer Correct ? | 51 Yes | 37 No |
Answer / sahanaj rahaman
max seat=9
so for different number...can write
(9+8+7+6+5+1)=36
so free spot=23-6=17
| Is This Answer Correct ? | 18 Yes | 13 No |
Answer / aditya agrawal
9+8+7+6+5+1= 36 readers
so ,6 spots have different readers.
remainings are 23-6= 17.
17 spots are empty.
| Is This Answer Correct ? | 4 Yes | 2 No |
Answer / arun
16 is correct i take this problem 1+2+4+5+7+8+9
in this case answer is:23-7=16
| Is This Answer Correct ? | 6 Yes | 18 No |
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