how we can call xml file in java file using Android platform?
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Answer / raju
using getResource() we can get the outer resources and from there onwards we can get the IDs of each view components presented inside the XML.
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Answer / srinivas
by using setContentView(R.Layout.main) method we can load the xml files in Activity
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THERE ARE 4 SOURCE FILES WHICH CONTAINS SAME METADATA CREATE A TARGET THAT SHOULD DISPLAY THE FILE NAME ALONG WITH THE RECORD PLEASE SEND THE ANSWERFOR THIS QUESTION WITH MAPPING
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In Bioinformatics, a DNA sequence is made up of a combination of 4 characters, namely “A,C,G,T”. A subsequence of a given sequence of characters a0, a1, …an- 1, is any subset of the characters taken in order, of the form ai0 , ai1 ,…..aik-1 where 0 ≤ i0 <i1….< ik-1 ≤ n-1. For example in the sequence “A,C,G,T,G,T,C,A,A,A,A,T,C,G”, we can have subsequences “A,G,T”, “A,C,A,A” and many more. A subsequence is palindromic if it is the same whether read left to right or right to left. For instance, the sequence “A,C,G,T,G,T,C,A,A,A,A,T,C,G”, has many palindromic subsequences, including “A,C,G,C,A” and “A,A,A,A” (on the other hand, the subsequence “A,C,T” is not palindromic). Devise an algorithm (using dynamic programming) that takes a sequence of characters X[0 … n-1] from the alphabet set (A,C,G,T) and returns the (length of the) longest palindromic subsequence. Implement the algorithm in an appropriate language.
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