Answer / sreejesh1987

#include<stdio.h>
#include<conio.h>
void main()
{
int i,flag=0;
float s,a[4];
clrscr();
printf("Enter Five numbers:");
for(i=0;i<5;i++)
scanf("%f",&a[i]);

printf("Enter a number to search:");
scanf("%f",&s);

for(i=0;i<5;i++)
if(a[i]==s)
flag=1;

if(flag==1)
printf("\nSearch number found");
else
printf("Search number not found");


getch();
}

Answer / pratap

yes

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1+1/2!+1/3!+...+1/n!

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Display Pattern: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 &#8230;

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#include<iostream.h> //main() //{ class A { friend class B; public: void read(); }; class B { public : int a,b; }; void A::read() { cout<<"welcome"; } main() { A x; B y; y.read(); } In the above program......, as B is a friend of A B can have access to all members,i cant access y.read . could you please tell me the reason and what would i code to execute this program?

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how to find out the maximum number out of the three inputs.

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can we declare an object of a class in another class?(assume both class as public classes)

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