Write a program to print prime nums from 1-20 using c
programing?
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Answer / dinesh
#include<stdio.h>
main()
{
int i,j;
for(i=2;i<=20;i++)
{
c=1;
for(j=2;j<i;j++)
{
if(i%j==0)
c=0;
}
if(c==1)
printf("%d",i);
}
}
| Is This Answer Correct ? | 46 Yes | 21 No |
Answer / ruth
#include<stdio.h>
#include<conio.h>
void main()
{
int i,j,s;
printf("prime number 1 to 20 :\n");
for(i=1;i<=20;i++)
{
s=0;
for(j=2;j<i;j++)
{
if(i==1)
s=0;
else if(i%j==0)
s=1;
}
if(s==0)
printf("%d\t",i);
}
getch();
}
| Is This Answer Correct ? | 18 Yes | 3 No |
Answer / binati mishra
prime number 1 to 20:
1 2 3 5 7 11 13 17 19
| Is This Answer Correct ? | 31 Yes | 17 No |
sorry for above output mistake:
output :1 2 5 7 11 13 17 19
| Is This Answer Correct ? | 21 Yes | 17 No |
Answer / bheem rao
#include<stdio.h>
#include<conio.h>
void main()
{
int i,j,count=0;
for(i=2;i<=20;i++)
{
for(j=1;j<=i;i++)
{
if(i%j==0)
count++;
}
if(count==2)
printf("%d\n",i);
count=0;
}
}
| Is This Answer Correct ? | 12 Yes | 8 No |
Answer / sreejesh1987
//Ha Ha I'm the creator of shortest code
//for prime numbers
#include<stdio.h>
#include<conio.h>
void main()
{
int i,j;
clrscr();
printf("\t\t\tPRIME NUMBERS 1-20\n");
printf("\n\t2");
for(i=3;i<=20;i++)
for(j=2;j<i,i%j!=0;j++)
if(i-1==j)
printf("\n\t%d",i);
getch();
}
| Is This Answer Correct ? | 6 Yes | 3 No |
Answer / ritu
Write a program to generate the first n terms in the series --- 2,3,5,7,11,...,17
| Is This Answer Correct ? | 5 Yes | 2 No |
Answer / rupamrox
#include<stdio.h>
#include<conio.h>
main()
{
int i,j,prime;
clrscr();
for(i=2;i<20;i++)
{
prime=1;
for(j=2;j<i;j++)
{
if(i%j==0)
prime=0;
}
if(prime==1)
printf("%d",i);
}
getch();
}
| Is This Answer Correct ? | 9 Yes | 7 No |
Answer / aniruddha tripathi
#include<stdio.h>
#include<conio.h>
#include<math.h>
void main()
{
int n,m,i;
clrscr();
printf("\n ENTER THE NUMBER");
scanf("%d",&n);
i=2;
ab:mfmod(n,i);
if(m==0);
{
printf("\n it is not prime");
goto bc;
]
else
{
i=i+1;
if(i<=(n-1))
{
goto ab;
}
printf("\n it is a prime no.");
}
bc;
getch();
}
| Is This Answer Correct ? | 3 Yes | 1 No |
Answer / r@m$
#include<stdio.h>
void main(){
int x;
for(x=2;x<=20;x++){
if(x<4)
printf("%d\t",x);
else
if(x%2!=0 && x%3!=0)
printf("%d\t",x);
}
}
| Is This Answer Correct ? | 0 Yes | 1 No |
What is the result main() { char c=-64; int i=-32 unsigned int u =-16; if(c>i){ printf("pass1,"); if(c<u) printf("pass2"); else printf("Fail2");} else printf("Fail1); if(i<u) printf("pass2"); else printf("Fail2") } a)Pass1,Pass2 b)Pass1,Fail2 c)Fail1,Pass2 d)Fail1,Fail2 e)none
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