Source table
-------------
ID NAME
--- ------
101 PANKAJ
NULL KUMAR
NULL MATHUR
102 JYOTI
NULL SAXENA
103 SACHIN
NULL TENDULKAR
TARGET TABLE
-------------
ID NAME
--- -------
101 PANKAJ KUMAR MATHUR
102 JYOTI SAXENA
103 SACHIN TENDULKAR
How to do the above scenario in Informatica.
Answers were Sorted based on User's Feedback
Answer / babu
Hi Sbvprasad,
Your answer has small correction,
V1=iif(not isnull (id),id,v1)
for the 1st record.
V1= iif( not isnull (101), then pass 101).
now the V1 variable having the value = 101.
2nd record
V1= iif( not isnull ( null), then pass else condition V1 (
having 101 ))
now the V1 variable having the value = 101.
3rd record
V1= iif( not isnull ( null), then pass else condition V1 (
having 101 ))
now the V1 variable having the value = 101.
After applied the above logic we will get the output as
mentioned below.
-------------
ID NAME
--- ------
101 PANKAJ
101 KUMAR
101 MATHUR
102 JYOTI
102 SAXENA
103 SACHIN
102 TENDULKAR
2.Take an EXP t/r,in this t/r declare two variable ports
for ID and Name columns.those are PRV_ID and VAR_NAME
VAR_NAME=IIF(PRV_ID=ID,VAR_NAME||' '||NAME,NAME)
PRV_ID=ID
OP_NAME=VAR_NAME (OUTPUT PORT)
3.In the next step take the aggregator transformation and
group by on the ID COLUMN. Then you will get the result.
TARGET TABLE
-------------
ID NAME
--- -------
101 PANKAJ KUMAR MATHUR
102 JYOTI SAXENA
103 SACHIN TENDULKAR
MAPPING ::
---------
SRC-->SQ-->EXP-->EXP-->AGGR-->TRG
IF ANY THING WRONG, PLEASE CORRECT WITH PROPER SOLUTION.
| Is This Answer Correct ? | 2 Yes | 0 No |
Answer / nagraj
From SQ pass to Expression Transformation
- Take Variable for ID i.e.
V_ID =iif(not isnull(ID),ID ,V_ID )
- Take Variable for Name i.e.
iif( isnull(ID) ,CONCAT(CONCAT(LTRIM(RTRIM
(V_old_Name)),' ') ,Name),Name)
At this stage you will see the Data like this
ID Name
101 PANKAJ
101 PANKAL KUMAR
101 PANKAJ KUMAR MATHUR
Now pass the ID and NAME output port through an Aggregator
Transformation
-Take new variable for Name i.e.
New_Name=concat(concat(New_Name,' '),Name)
-Take new output port for Name and put expression for the
Name output port as follows
Out_Name=GREATEST(Name,New_Name)
- Check Group By on ID
Pass the ID and Name outpurt port to the Target.
option (truncate and load)
Where Group by on ID port
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / sbvprasad
V1=iif(not isnull (id),id,v1)
for the 1st record.
V1= iif( not isnull (101), then pass 101).
now the V1 variable having the value = 101.
2nd record
V1= iif( not isnull ( null), then pass else condition V1 (
having 101 ))
now the V1 variable having the value = 101.
3rd record
V1= iif( not isnull ( null), then pass else condition V1 (
having 101 ))
now the V1 variable having the value = 101.
After applied the above logic we will get the output as
mentioned below.
-------------
ID NAME
--- ------
101 PANKAJ
101 KUMAR
101 MATHUR
102 JYOTI
102 SAXENA
103 SACHIN
102 TENDULKAR
2.In the next step take the aggregator transformation and
group by on the id. Then you will get the result.
TARGET TABLE
-------------
ID NAME
--- -------
101 PANKAJ KUMAR MATHUR
102 JYOTI SAXENA
103 SACHIN TENDULKAR
| Is This Answer Correct ? | 3 Yes | 8 No |
Whats there in global repository
Write the advantages of partitioning a session?
Can we have a Mapping without a Source Qualifier?
What is mapplet and a reusable transformation?
Explain the shared cache and re-cache?
What is the difference between writing a joiner query in ANSI style and THETA style?
What you know about transaction control transformation?
How many ways a relational source definition can be updated and what are they?
how to duplicates from expression transformation without using sorter before that
how lookup is acting as both active and passive ? how is it possitble?
follwing scenario two table using find maximum salary? table a table b 101 xxx 1000 106 6500 103 yyy 5000 108 800 104 din 6000 109 7000 105 dsh 200 110 3000
Is it passive or active when check and uncheck the box of DISTINCT in Sorter transformation? why?
6 Answers iFlex, Morgan Stanley,