void main() { char c; while(c=getchar()!='\n') printf(&quo

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void main()
{
char c;
while(c=getchar()!='\n')
printf("%d",c);
}
o/p=11 why?

Question Posted / biren

8 Answers
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void main() { char c; while(c=getchar()!='\n') printf("%d",c); } ..

Answer / biren

Is This Answer Correct ?

9 Yes

5 No

void main() { char c; while(c=getchar()!='\n') printf("%d",c); } ..

Answer / suman halder

test cases:
1.
i/p:hi
o/p:11

2.
i/p:hello
o/p:11111

actually,getchar reads from stdin and is line buffered which means it will not return until you press ENTER.

so,look at the evaluation of the expression(c=getchar()!='\n')
here,
getchar()!='\n' evaluates to true until and unless u'll hit enter..that is why,the actual evaluation would look like
(c=(getchar()!='\n'))
so,
1 will be stored into c each time u press a key except enter key as (getchar()!='\n') evaluates to 1(true value of an expression).

finally,content of the buffer would get printed..
thats it..

Is This Answer Correct ?

4 Yes

1 No

void main() { char c; while(c=getchar()!='\n') printf("%d",c); } ..

Answer / hari.11

above friend has posted correct answer,
11 is not the correct answer,
it will take all characters into buffer and will not output any answer until we press '\n' character.
So it would print 1 as many times as number of character pressed before '\n'.

e.g.:
s
o/p: 1

sd
o/p: 11

gdfdd
o/p: 11111

111
o/p: 111

for further queries and discussions, visit..

http://forum.campusmaniac.com/
http://www.campusmaniac.com/

Is This Answer Correct ?

2 Yes

1 No

void main() { char c; while(c=getchar()!='\n') printf("%d",c); } ..

Answer / sumeet saini

It says %d which means it prints integer value. If we want to print character we need to write %c. So the answer is right. If we replace %d with %c . This program will print what ever character we hit from keyboard until we press enter

Is This Answer Correct ?

1 Yes

0 No

void main() { char c; while(c=getchar()!='\n') printf("%d",c); } ..

Answer / abdul qadir

11 is a garbage value at address in memory

Is This Answer Correct ?

6 Yes

6 No

void main() { char c; while(c=getchar()!='\n') printf("%d",c); } ..

Answer / satya

I Think ascii value of \n is 92.

Is This Answer Correct ?

2 Yes

2 No

void main() { char c; while(c=getchar()!='\n') printf("%d",c); } ..

Answer / prashant

The answer would have been 11 only if the while statement would have had a semicolon to finish with , i.e. "while(c=getchar()!='\n');" According to the above code it will generate the ascii of all the characters entered except the newline character.

Regards
Prashant

Is This Answer Correct ?

0 Yes

1 No

void main() { char c; while(c=getchar()!='\n') printf("%d",c); } ..

Answer / deepshree sinha

the while loop is continue until the expression is not false.
when the expression is false that is when c='\n' it will come
out from the loop.then it will print c which is equal to '\n'
whose integer value is 11.so it will print 11.

Is This Answer Correct ?

0 Yes

1 No

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