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void main()
{
char c;
while(c=getchar()!='\n')
printf("%d",c);
}
o/p=11 why?
- 8 Answers
- 13137 Views
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Answer / suman halder
test cases:
1.
i/p:hi
o/p:11
2.
i/p:hello
o/p:11111
actually,getchar reads from stdin and is line buffered which means it will not return until you press ENTER.
so,look at the evaluation of the expression(c=getchar()!='\n')
here,
getchar()!='\n' evaluates to true until and unless u'll hit enter..that is why,the actual evaluation would look like
(c=(getchar()!='\n'))
so,
1 will be stored into c each time u press a key except enter key as (getchar()!='\n') evaluates to 1(true value of an expression).
finally,content of the buffer would get printed..
thats it..
| Is This Answer Correct ? | 4 Yes | 1 No |
Answer / hari.11
above friend has posted correct answer,
11 is not the correct answer,
it will take all characters into buffer and will not output any answer until we press '\n' character.
So it would print 1 as many times as number of character pressed before '\n'.
e.g.:
s
o/p: 1
sd
o/p: 11
gdfdd
o/p: 11111
111
o/p: 111
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| Is This Answer Correct ? | 2 Yes | 1 No |
Answer / sumeet saini
It says %d which means it prints integer value. If we want to print character we need to write %c. So the answer is right. If we replace %d with %c . This program will print what ever character we hit from keyboard until we press enter
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / prashant
The answer would have been 11 only if the while statement would have had a semicolon to finish with , i.e. "while(c=getchar()!='\n');" According to the above code it will generate the ascii of all the characters entered except the newline character.
Regards
Prashant
| Is This Answer Correct ? | 0 Yes | 1 No |
Answer / deepshree sinha
the while loop is continue until the expression is not false.
when the expression is false that is when c='\n' it will come
out from the loop.then it will print c which is equal to '\n'
whose integer value is 11.so it will print 11.
| Is This Answer Correct ? | 0 Yes | 1 No |
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