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void main()
{
char c;
while(c=getchar()!='\n')
printf("%d",c);
}
o/p=11 why?
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Answer Posted / suman halder
test cases:
1.
i/p:hi
o/p:11
2.
i/p:hello
o/p:11111
actually,getchar reads from stdin and is line buffered which means it will not return until you press ENTER.
so,look at the evaluation of the expression(c=getchar()!='\n')
here,
getchar()!='\n' evaluates to true until and unless u'll hit enter..that is why,the actual evaluation would look like
(c=(getchar()!='\n'))
so,
1 will be stored into c each time u press a key except enter key as (getchar()!='\n') evaluates to 1(true value of an expression).
finally,content of the buffer would get printed..
thats it..
| Is This Answer Correct ? | 4 Yes | 1 No |
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