Interested to Buy Any Domain ? << Click Here >> for more details...
A car travels from B at a speed of 20 km/hr. The bus travel
starts from A at a time of 6 A.M. There is a bus for every
half an hour interval. The car starts at 12 noon. Each bus
travels at a speed of 25 km/hr. Distance between A and B is
100 km. During its journey , The number of buses that the
car encounter
- 3 Answers
- 15278 Views
- CTS, TCS, I also Faced
- E-Mail Answers
Answers were Sorted based on User's Feedback
Answer / naren.bhupathy
Excluding the buses that start at 8 and 5 the answer will be 17..
8.30,9,9.30,10,10.30,11,11.30,12,12.30,1,1.30,2,2.30,3,3.30,4,4.30...
totally it comes to 17 !!!!
| Is This Answer Correct ? | 36 Yes | 1 No |
Answer / sagar
The Bus that starts at 8 in the morning will meet the car at B at 12, when it (car) is starting its journey. The car will be travelling till 5 in the evening, so it will meet all the buses till that time. That makes the total number to be 18, but since it meets the 8 A.M. bus and the 5 P.M. Bus at stand still and not "During the journey" so the correct answer would be 16.
| Is This Answer Correct ? | 8 Yes | 15 No |
Answer / akbar
car requires 5 hrs to reach A. ie from 12pm to 5pm. during
these hrs buses that starts from 8.30 will be in the way to
B because bus requires 4hrs to reach B. the last bus that
car encounter is the one which starts at 12.30pm.
hence no of buses are 9 :)
| Is This Answer Correct ? | 10 Yes | 23 No |
types of shares
given 2 cubes,arrange any number from 0-9 so dat wen put together whole month dates should appear.
a=2,b=3,c=6 c/(a+b)-(a+b)/c=?
Find the next number in the series 1,2,5,10,,15,22--
A person runs 6 ft in 1/4 sec. how much it will run in 10 sec.
Two trains are travelling at equilateral .Train A is travelling in the direction of earths spin.Other train B is travelling in opposite direction of earths spin.Which trains wheels will wear first?and why?
(998-1)(998-2)(998-3).....(998-n)= ? when n>1000
3,5,7,12,17,19,..????
which questions will be coming
fridge cost R Rs,cover value is 5,discount d% then its new cost?
in pure milk if 20% replaced by water and in this again 20% is replaced by water and again 20% is replaced by water then what is the proportion of milk in that mixture
18.8 * 8.8 * 28.8 can anyone tell simple method to calculate this without normal multiplication?
English 
