struct node {struct node*temp,*new} prinf("%d",sizeof(struct node));

struct node {struct node*temp,*new}
prinf("%d",sizeof(struct node));

Question Posted / prasanth

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struct node {struct node*temp,*new} prinf("%d",sizeof(struct node));..

Answer / aravind

ok guys.
Here first structure is not ended with a
termination.Structure is nested with another
structure.Usually pointer takes 4 bytes for GCC compiler
and here he defined 2 pointers so o/p would be 8 bytes but
compiler shows error of being undeclared structure

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struct node {struct node*temp,*new} prinf("%d",sizeof(struct node));..

Answer / dani

It's architecture dependent. If you have a 32 bit address than the output will be 4 (octets), if the address is 64 bit than it'll be 8.

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