struct node {struct node*temp,*new}
prinf("%d",sizeof(struct node));
Answers were Sorted based on User's Feedback
Answer / aravind
ok guys.
Here first structure is not ended with a
termination.Structure is nested with another
structure.Usually pointer takes 4 bytes for GCC compiler
and here he defined 2 pointers so o/p would be 8 bytes but
compiler shows error of being undeclared structure
| Is This Answer Correct ? | 2 Yes | 0 No |
Answer / dani
It's architecture dependent. If you have a 32 bit address than the output will be 4 (octets), if the address is 64 bit than it'll be 8.
| Is This Answer Correct ? | 0 Yes | 1 No |
main() { int x=5,y=10,z=0; x=x++ + y++; y=y++ + ++x; z=x++ + ++y; printf("%d%d%d\n",x,y,z); }
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