A dishonest hairdresser uses a mixture having 5 parts after-shave lotion and
3 parts water. After
taking out some portion of the mixture, he adds equal amount of water to the
remaining portion
of mixture such that the amount of after shave lotion and water become
equal. Find the part of
mixture taken out.
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Answer / rajat
**
the portion taken out will be in the ratio 5:3.
let the portion taken out be 'x'
so it is removed in the ratio 5:3
ie
5-(5/8)x and 3 - (3/8)x
since 'x' parts of water is again added, the eqn should be
5-(5/8)x = 3 -(3/8)x + x
=> 2= (5/4)x
hence x=8/5
INITIALLY WE HAVE ASSUMED THAT THEIR IS 8 UNITS SOLUTION SO PART REMOVED COMES OUT TO BE 8/5.
THEREFORE ACTUAL PART OF MIXTURE TAKEN OUT IS 8/5/8 = 1/5.
| Is This Answer Correct ? | 49 Yes | 4 No |
Answer / niks
the portion taken out will be in the ratio 5:3.
let the portion taken out be 'x'
so it is removed in the ratio 5:3
ie
5-(5/8)x and 3 - (3/8)x
since 'x' parts of water is again added, the eqn should be
5-(5/8)x = 3 -(3/8)x + x
=> 2= (5/4)x
hence x=8/5
| Is This Answer Correct ? | 7 Yes | 20 No |
Answer / akbar
here we have 5 part shave lotion(S) and 3 part water(W) so
mixture will be 5 + 3 = 8 part. we are removing some part
say X from mixture (ie 8 part) and again adding X part
water in it. so final mixture remains same 8 part. now we
will be having equal part of S and W which is nothing but 4
part S and 4 Part W. so X must be 3 = 1S + 2W
5 + 3 = 8;
8 - 3(ie 1S + 2W) = 5;
5 + 3W = 8(4S + 4W);
:)
| Is This Answer Correct ? | 0 Yes | 14 No |
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