write a function that accepts an array A with n elements and
array B with n-1 elements. Find the missing one in array
B,with an optimized manner?
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Answer / vaibhav nigam
// missing number= diff in sum of 2 arrays
int missing_number(int A[], int B[], int n)
{
int sum1=0;
for(int i=0; i<n; i++) {
sum1+=A[i];
}
int sum2=0;
for(int i=0; i<n-1; i++) {
sum2+=B[i];
}
return (sum1-sum2);
}
Is This Answer Correct ? | 2 Yes | 0 No |
Answer / aravind
#include<stdio.h>
int missing_item(int,int);
int main()
{
int a[10];
int b[9];
printf("enter size of array");
scanf("%d",&n);
for(i=0;i<n;i++)
{
printf("enter the elemets of array a ");
scanf("%d",&a);
}
for(i=0;i<n-1;i++)
{
printf("enter b elements");
scanf("%d",&b);
missing_item(int c,int d)
{
int item;
for(i=0;i<n;i++)
{
if(c[i]==d[i])
break;
else
{
item=c[i];
printf("the missing item is=%d",c[i]);
}
}
Is This Answer Correct ? | 0 Yes | 2 No |
Given a string write a program to print all alphabetical characters in the order of their occurance first,followed by the sum of the numeric characters then followed by the special characters in the order of their occurance.
1 Answers College School Exams Tests, Wipro,
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change to postfix a/(b+c*d-e)
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