suppose you build a tower interlocking cubes that is 99
cubes high. And suppose you have to paint each square on
the tower. How many squares would you have to paint?
Answers were Sorted based on User's Feedback
Answer / kiran
its 396.. 99*4 + 1 =397. Because top most cube will have 5
faces to be painted.
Is This Answer Correct ? | 53 Yes | 2 No |
Answer / asaranprasad
397...
topmost cube needs 5 sides painting
rest 98 cubes need oly 4 side painting
Is This Answer Correct ? | 5 Yes | 0 No |
Answer / narsee
Actually my previous answer needs some right calculation
its not 395 ..... its 397
Is This Answer Correct ? | 4 Yes | 0 No |
Answer / pradeepanandh
the top cube has 5 squares to b painted and remaining 98
cubes have 4 sides to paint..
so
98*4=392
then top cube have 5 sides to b painted
hence
392+5=397
Is This Answer Correct ? | 2 Yes | 0 No |
Answer / abdul
the top cube has 5 squares to be painted and the remaining
98 cubes have 4 sides to paint.
so you multiply 98*4=392 .
THEN THE TOP OF THE CUBE HAS 5 SIDES TO BE
PAINTED .392+5=397
answer is 397
Is This Answer Correct ? | 1 Yes | 0 No |
Answer / narsee
(99*6)-(98*2)-1 = 395
because,
Total squares 594
out of 594, 197 (2 squares from bottom 98 cubes and bottom
square of the top cube) can be left.
Is This Answer Correct ? | 2 Yes | 4 No |
Answer / b subrahmanyam
They are to be 4 cubes high.because a cube contains four side so 99.....99*4=396
cube multiplied by 4
Is This Answer Correct ? | 1 Yes | 4 No |
Answer / arun
its 396.. 99*4=396. because a cube contains four side so 99
cube multiplied by 4
Is This Answer Correct ? | 12 Yes | 18 No |
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