Three containers are of 15,10 and 6 ltrs capacity.
Initially its in configuration (15,0,0). Make it to
configuration (2,8,5).
Answers were Sorted based on User's Feedback
Answer / md
In my understanding this is not possible.
reason:
the final state expected is below [ no is () is the
capacity of the respective container. ]
2(15) 8(10) 5(6)
None of teh container is full.
Lets try for a back calculation.
What can be the last step, so that it results 2lt 8lt and 5
lt is respective containers..
Now the prob is you wont find a answr of it.
assume the last step to achieve this ... was pouring x lt
of lequid from 1st to 2nd. so 1st had 2+x lt and 2nd had 8-x
Now how would one measure this x amount?.. Usually in such
cases measurement comes from container's capacity. Hence at
any state at least one container has to be totally full or
totally empty
see example below:
15 0 0
9 0 6 - 3rd is totally full
0 9 6 - 3rd is totally full
6 9 0 - 3rd is totally empty [when none is totally full]
5 10 0 - 2nd is totally full
0 10 5 - 2nd is totally full
I cant derive any state out of it... where all are partly
full.
Hence the solution expected is not possible to derive
without additional equipment.
| Is This Answer Correct ? | 10 Yes | 2 No |
Answer / nitish
assuming
half the volume can b calculated using tiltin the container
to da point where the level is diagonal to the container.
thus config can be
15 0 0
9 0 6
9 6 0
3 6 6
3 10 2
now half of middle to the first
8 5 2(now shift the containers to desired pos :P)
| Is This Answer Correct ? | 0 Yes | 5 No |
Answer / karthikeyan
pore 5 lts from first container to the last container and 8
lts into the second container
| Is This Answer Correct ? | 2 Yes | 8 No |
Answer / aditya
fill the last container from the first that is 6 litre will
be deducted from 15.
now first will have 9 and third will have 6,
now empty the first one into second one therefore second
will now have 9 litres and third will be 6(unchanged)
first is now zero.
now empty 1 litre from third one into second one,so as to
make second one full i.e. 10 litre.
so third now will have 5 litre,and second will have 10
litre,and first is now zero.
now fill first with 2 litre from second one.
| Is This Answer Correct ? | 1 Yes | 8 No |
Answer / saginu
Required: 2 8 5
U hv: 15 0 0
STEP1: 9 0 6
STEP2: 9 6 0
STEP3: 3 6 6
STEP4: 3 10 2
STEP5: 13 0 2
STEP6: 13 2 0
STEP7: 8 2 5 (ANS: If the position does't matter)
| Is This Answer Correct ? | 3 Yes | 12 No |
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