Answer / @m@n

In 1 try..
if we take 1 coin from first box..
2 coins from 2nd box..
3 from third.. 4 4m 4th box and 5 coins 4m 5th box..
after taking the coins ... weight those coins...nw total
num of coins we take is 15...
nw if the weight will b 1490 gm thn 90gm coins in first
box.. if d weight 'll b 1480gm thn 90gm coins in 2nd box...
and similarly in case of 3,4 and 5 box...

Answer / paul

If the weighing tool is a digital measurement (not a balance instrument). My answer is 1 try.

My solution:

First you must collect the necessary balls from each box in an order like this:

collect 1 ball from box 1
collect 2 balls from box 2
collect 3 balls from box 3
collect 4 balls from box 4 &
collect 5 balls from box 5

Total balls you have collected is 15 balls.

To determine which box contains the 90 grm balls, you must
weigh all the 15 balls in the digital measurement. If the
result of measurement is:

5*90 + 100*10 then the answer is the 5th box
4*90 + 100*11 then the answer is the 4th box
3*90 + 100*12 then the answer is the 3rd box
2*90 + 100*13 then the answer is the 2nd box
1*90 + 100*14 then the answer is the 1st box

Answer / pallavimudradi

1 try

Answer / nelwin

min 1
remove any 1 box.and weigh 2 boxes each on digital bal..if
weights r same then removed box is 90gm box..

max 2

repeat same..if weights differ then remove the boxes wid
more weigs..dats is wid 100gms..again weigh each box of
separately..u wil get it..

Answer / bala

min 2,
weight 2 boxes on each side, if weights are same then
remaining box is 90gms. if not take the boxes from less
balanced side and weight them again.

Answer / guest

3

Answer / paul

Minimum is 1 try and maximum is 2 tries. That is, assuming that all boxes contain same quantity of coins each.

verify...

First, lets label the boxes a,b,c,d and e.
Then measure and balance a+b if equals to c+d.

Condition 1
If the 4 boxes balanced, then box e has the 90gm coins. Thus, answering promptly with only 1 try (Minimum).

Condition 2
If (a+b) < (c+d), then it can be observed that either box a or b has the 90 gm coins. Thus, balancing again box a vs b will give you the box with the 90 gm coins, that is, with the lower weight between the 2 boxes. Thus, obtaining the answer with 2 tries.

Condition 2
If (a+b) > (c+d), then it can be observed that either box c or d has the 90 gm coins. Thus, balancing box c against box d will give you the box with the 90 gm coins, that is, with the lower weight between the 2 boxes. Thus, obtaining the answer with 2 tries.

Answer / sameer k

answer :::min 2 and max 3
calc weight of 3 box, there are 2 condition
condition 1(min 2)>>if the weight of 3 boxes is (90*3)270
then, take any 1 box from other 2boxes
calc weight is weight
condition 2(max 3)>>if weight of 3 boxes is greater than 270
that means among 3 boxes there is a box whose
weight is greater than 90, then calc the weight of any 2
from them if egals 180 then third box weight is 100gm

13.333*19.111=?

11 Answers   TCS,

i want model paper on SBI Clerk post,plz sed previous papers

56 Answers   Abhyudaya Co-operative Bank, BMC, Clerical Jobs, JAS, Rohit Technologies, State Bank Of India SBI,

There are 8 coins in a bag . 3 coin weights x kg 3 coins weights y kg 2 coins weights z kg 2 coins weights w kg You have to separate them into separate heaps according to their weights .

1 Answers   Oracle,

A man is going to an Antique Car auction. All purchases must be paid for in cash. He goes to the bank and draws out $25,000. Since the man does not want to be seen carrying that much money, he places it in 15 evelopes numbered 1 through 15. Each envelope contains the least number of bills possible of any available US currency (i.e. no two tens in place of a twenty). At the auction he makes a successful bid of $8322 for a car. He hands the auctioneer envelopes number(s) 2, 8, and 14. After opening the envelopes the auctioneer finds exactly the right amount. How many ones did the auctioneer find in the envelopes?

2 Answers  

Take 5 Zero's and perform any mathematical opretion on them to make ans 120. (can't use any number)

16 Answers   CitiGroup, FIITJEE, MAHINDRA,

how many zeros are there at the end of product between 1 to 100

47 Answers   Infosys, SIP, TATA, Tech Mahindra, Vodafone,

I'm something, i appear twice in a week but none in a day.I appear once in a year but none in a month. what am i?

6 Answers   Oliver,

How long would it take you to count 1 billion orally if you could count 200 every minute and were given a day off every four years?

5 Answers  

Difference between Bholu's and Molu's age is 2 years and the difference between Molu's and Kolu's age is 5 years. What is the maximum possible value of the sum of the difference in their ages, taken two at a time?

2 Answers  

ek cricket match chal raha he jitne ke liye 7 ball me 3 runs lag rahe he. dono batsman ke runs he 94and 94. 3 balls me se koi bhi whide,extra, noball nahi gira.fir bhi dono batsman ne centuri puri ki.aur teem match jeet gayi. to dono batsman ne apni centuri puri ki kese?

13 Answers  

At the entrance to a members club stands a stranger seeking admission. A friend told him that it's easy to get in. You just have to answer a question corrcetly! Answering wrong, however, will result in being shot! To live a little longer, the man waits in a back alley near the entrance for people to go in. After a while a man comes to the entrance. The door warden asks him: "Twelve?" to which he replies "Six!" and goes in. "That's easy." our friend thinks, but he waits a little longer. Another man comes to the door. "Six?" the door warden asks, to which he replies "Three!" and goes in. "That's too good to be true" our friend thinks, and he was right. Because, when asked "Four?", he answered "Two!" and was found dead in the alley. What was the correct answer?

1 Answers  

A cube painted on all six sides by red color is divided into 125 equal cubes find i) number of cubes having a)3 faces colored b)2 faces colored c) 1 face colored d)0 faces colored ii)Find probability of picking a cube having red face

6 Answers   Infosys,