Hi all,
I need query help for below senorio, could you please help
me.
TableName = City
CITYID ContinuationID CITYNAME
1 1 SAN
1 2 DIEGO
2 1 SAN
2 2 FRANCISCO
3 1 CHICAGO
4 1 NEW
4 2 YORK
4 3 CITY
Could you please help me to write a generalized SQL that
returns results as given below in the
Query result
CITYID NAME1 NAME2 NAME3 NAME4 NAME5
1 SAN DIEGO
2 SAN FRANCISCO
3 CHICAGO
4 NEW YORK CITY
Answers were Sorted based on User's Feedback
Answer / prakash
CREATE TABLE CITY (CITYID INT, ContinuationID INT, CITYNAME
VARCHAR(50))
GO
INSERT CITY
SELECT 1 ,1, 'SAN'
UNION ALL
SELECT 1, 2, 'DIEGO'
UNION ALL
SELECT 2, 1, 'SAN'
UNION ALL
SELECT 2, 2, 'FRANCISCO'
UNION ALL
SELECT 3, 1, 'CHICAGO'
UNION ALL
SELECT 4, 1, 'NEW'
UNION ALL
SELECT 4, 2, 'YORK'
UNION ALL
SELECT 4, 3, 'CITY'
SELECT cityid,
max(CASE P.ContinuationID WHEN 1 THEN
P.CITYNAME ELSE '' END) AS Name1,
max(CASE P.ContinuationID WHEN 2 THEN
P.CITYNAME ELSE '' END) AS Name2,
max(CASE P.ContinuationID WHEN 3 THEN
P.CITYNAME ELSE '' END) AS Name3
FROM CITY AS P
GROUP BY P.cityid
| Is This Answer Correct ? | 8 Yes | 0 No |
Answer / gopi muluka
Using PIVOT operator we can achieve this in SQL 2005
CREATE TABLE CITY (CITYID INT, ContinuationID INT, CITYNAME
VARCHAR(50))
GO
INSERT CITY
SELECT 1 ,1, 'SAN'
UNION ALL
SELECT 1, 2, 'DIEGO'
UNION ALL
SELECT 2, 1, 'SAN'
UNION ALL
SELECT 2, 2, 'FRANCISCO'
UNION ALL
SELECT 3, 1, 'CHICAGO'
UNION ALL
SELECT 4, 1, 'NEW'
UNION ALL
SELECT 4, 2, 'YORK'
UNION ALL
SELECT 4, 3, 'CITY'
GO
SELECT CITYID, [1] AS NAME1,[2] AS NAME2,[3] AS NAME3, [4]
AS NAME4
FROM
(
SELECT CITYID,ContinuationID, CITYNAME
FROM CITY
) P
PIVOT
(
MAX(CITYNAME)
FOR ContinuationID IN
([1],[2],[3],[4])
) AS PVT
ORDER BY CITYID
GO
DROP TABLE CITY
| Is This Answer Correct ? | 5 Yes | 0 No |
Answer / sandeep modapathi
Hi all
Gopi Muluka is right... but here I'm posting one different
thing.. ie the out put will be like this
Only two columns
It uses a function for concatination
CityID CityName
1 SAN DIEGO
2 SAN FRANCISCO
3 CHICAGO
4 NEW YORK CITY
CREATE FUNCTION DBO.GROUP_CONCAT(@CITYID VARCHAR(100))
RETURNS VARCHAR(8000)
AS
BEGIN
DECLARE @STRING VARCHAR(8000)
SET @STRING=''
SELECT @STRING=@STRING+' ' +CITYNAME FROM CITY
WHERE CITYID=@CITYID ORDER BY CONTINUATIONID
RETURN LTRIM(@STRING)
END
select distinct CITYID,dbo.GROUP_CONCAT(CITYID)as CityName
from city
| Is This Answer Correct ? | 1 Yes | 0 No |
How about this, a single dynamic query:
create table cities (CITYID int, ContinuationID int,
CITYNAME varchar(50))
insert into cities
select 1, 1, 'SAN' UNION
select 1, 2, 'DIEGO' UNION
select 2, 1, 'SAN' UNION
select 2, 2, 'FRANCISCO' UNION
select 3, 1, 'CHICAGO' UNION
select 4, 1, 'NEW' UNION
select 4, 2, 'YORK' UNION
select 4, 3, 'CITY' UNION
select 5, 1, 'CITY1' UNION
select 5, 2, 'CITY2' UNION
select 5, 3, 'CITY3' UNION
select 5, 4, 'CITY4' UNION
select 5, 5, 'CITY5'
select * from cities
select distinct CITYID,
case
when exists(select ContinuationID from cities
where CITYID = c.CITYID and ContinuationID=1)
then (select CITYNAME from cities
where CITYID = c.CITYID and ContinuationID=1)
else ''
end as name1,
case
when exists(select ContinuationID from cities
where CITYID = c.CITYID and ContinuationID=2)
then (select CITYNAME from cities
where CITYID = c.CITYID and ContinuationID=2)
else ''
end as name2,
case
when exists(select ContinuationID from cities
where CITYID = c.CITYID and ContinuationID=3)
then (select CITYNAME from cities
where CITYID = c.CITYID and ContinuationID=3)
else ''
end as name3,
case
when exists(select ContinuationID from cities
where CITYID = c.CITYID and ContinuationID=4)
then (select CITYNAME from cities
where CITYID = c.CITYID and ContinuationID=4)
else ''
end as name4,
case
when exists(select ContinuationID from cities
where CITYID = c.CITYID and ContinuationID=5)
then (select CITYNAME from cities
where CITYID = c.CITYID and ContinuationID=5)
else ''
end as name5
from cities c
where ContinuationID=1
drop table cities
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / das
select cityid,group_concat(cityname) as city from city group by cityid;
| Is This Answer Correct ? | 0 Yes | 1 No |
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