int main()
{
int x = (2,3,4);
int y = 9,10,11;
printf("%d %d",x,y);
}
what would be the output?
Answers were Sorted based on User's Feedback
Answer / samrat
Ans is: 4,9
For example
int i = (x, y); // stores y into i
int i = x, y; // stores x into i
Is This Answer Correct ? | 5 Yes | 1 No |
Answer / vadivelt
1.Error. Because the syntax of statement int y = 9,10,11;
is wrong. it is not allowed to initialise a variable "int y
= 9,10,11;" with this syntax because it will be treated as
constant. But it is allowed to keep the values inside of
braces in the initialisation. ie., int x = (2,3,4);
2.If the program is written as like below, output would be
4 9.
int main()
{
int x, y;
x = (2,3,4);
y = 9,10,11;
printf("%d %d",x,y);
getch();
}
Cos the precedence of statement x = (2,3,4); is left to
right. and for y = 9,10,11; the precedence would be right
to left.
So the latest assigned values to x and y would be 4 and 9.
Is This Answer Correct ? | 4 Yes | 1 No |
Answer / saranya
you cant initialize values separated by commas for the variables,it may cause errors .so find to initialize properly before setting the values to the variables.
Is This Answer Correct ? | 1 Yes | 1 No |
Answer / kalyan chukka
in This Given x=(2,3,4) which takes priority from left->right
and given y=9,10,11 So in This it takes priority from right
-> left so answers are
X=4
Y=9
Is This Answer Correct ? | 1 Yes | 1 No |
Answer / ajay kumar
error:
because declaration terminated incorrectly.
Is This Answer Correct ? | 1 Yes | 1 No |
#include<stdio.h> main() { int a[3]; int *I; a[0]=100;a[1]=200;a[2]=300; I=a; Printf(“%d\n”, ++*I); Printf(“%d\n”, *++I); Printf(“%d\n”, (*I)--); Printf(“%d\n”, *I); } what is the o/p a. 101,200,200,199 b. 200,201,201,100 c. 101,200,199,199 d. 200,300,200,100
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