n=7623 { temp=n/10; result=temp*10+ result; n=

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n=7623
{
temp=n/10;
result=temp*10+ result;
n=n/10
}

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n=7623 { temp=n/10; result=temp*10+ result; n=n/10 } ..

Answer / guest

3267

Is This Answer Correct ?

12 Yes

7 No

n=7623 { temp=n/10; result=temp*10+ result; n=n/10 } ..

Answer / vikesh

n=temp=762
the value of result depends on initial value of result

Is This Answer Correct ?

8 Yes

3 No

n=7623 { temp=n/10; result=temp*10+ result; n=n/10 } ..

Answer / shruti

the answer depends upon, to what value result is
initialised..

Is This Answer Correct ?

6 Yes

2 No

n=7623 { temp=n/10; result=temp*10+ result; n=n/10 } ..

Answer / naresh lingampally

cool!!! ignoring the syntax errors;

n=7623
n/10== 762
result=>762*10+*;

this means that the result itself should be initialized to
'0' so that there would a right output..

So output will be garbage value ...
to my knowledge

Is This Answer Correct ?

2 Yes

0 No

n=7623 { temp=n/10; result=temp*10+ result; n=n/10 } ..

Answer / bobby shankar

it will display something garbage
because value of result is not
initialised .

Is This Answer Correct ?

2 Yes

0 No

n=7623 { temp=n/10; result=temp*10+ result; n=n/10 } ..

Answer / arif shaik

The variables n,tempand result what type data it may be?,It
first Displays an error "Statement missing ; in function
main". If it is rectified then the answer should depends on
data type of that variables and their initialized values.

Is This Answer Correct ?

2 Yes

1 No

n=7623 { temp=n/10; result=temp*10+ result; n=n/10 } ..

Answer / vignesh1988i

assuming that the variables that are used above are integers....

the result will be : depends on the user....

Is This Answer Correct ?

0 Yes

1 No

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