if we create a file, in that 10 rows(means 1,2,....9,10
like). i want 7 row exactly, which command use in unix?
plz send this question.
Answers were Sorted based on User's Feedback
Answer / soumendra
ans- cut -d " " -f 1-7 <file name>
by this u can get all the 7 rows of ur file.
here i give 'space" as the delimeter.
u give the delimeter as u give in the file.
by -f option u can exactly get the 1 to 7 field/rows
| Is This Answer Correct ? | 0 Yes | 1 No |
Answer / mo
Using VI editor this can be done like this.
type this command.
:1,7w <newfilename>
All Good
Mo
| Is This Answer Correct ? | 0 Yes | 2 No |
Answer / meenu
if u want first 7 rows then
head -n7 <filename>
but if you want only 7th row then
awk 'nr==7 {print}' <fileanme>
or
tail -n4 <filename>|head -n1
| Is This Answer Correct ? | 0 Yes | 6 No |
Hi All, Can you please let me know how to grep for a particular pattern in unix. I want to print the dates from the file exp.txt. the date pattern is DD:MM:YYYY, I just want to print all the dates from the file exp.txt.
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