what is the output of
printf("%d",(scanf("%d",10));
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Answer / ansh
This code when executes on a Turbo C compiler requires an
input from user and is giving 1 as output if one enters a
numeral value and 0 otherwise.
| Is This Answer Correct ? | 18 Yes | 7 No |
Answer / kamal
scanf() returns integer value for number sucessful entry taken.
Due to this cause of taking integer value at address 10 it
will print 1 otherwise 0;
| Is This Answer Correct ? | 11 Yes | 2 No |
scanf returns nos. of arguments taken by scanf hence it
will ask user to input and if integer is fed as I/P then
printf gives 1 as o/p
| Is This Answer Correct ? | 4 Yes | 1 No |
Answer / hema
In Unix enviroment, this gives warning while compilation
and core when executed with a user value. Since scanf
expects a variable( address) to store the value, whereas
here we are assinging value to constant.
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / umesh
#include<stdio.h>
int main ()
{
int c;
printf("%d",(scanf("%d",&c)));
return 0;
}
in this case return 1 instead of entering any value as input.
printf("%d",(scanf("%d",10)));
in this case simply generates a run time error. bcoz Since scanf always expects a variable( address) to store the value.
| Is This Answer Correct ? | 2 Yes | 1 No |
Answer / arti
tihis will return an runtime error as no address is pass in
scanf where value is to assign which we get as user input
through scanf().
| Is This Answer Correct ? | 3 Yes | 3 No |
Answer / kalyan chukka
Answer is 1 Because it prints how many values taken from
keyboard so it prints 1
| Is This Answer Correct ? | 3 Yes | 3 No |
Answer / neelamani
1 NULL pointer assignment
This output in TC compiler
| Is This Answer Correct ? | 5 Yes | 6 No |
Answer / karna
answer is 1.because it counts how many numbers are given as input
| Is This Answer Correct ? | 1 Yes | 3 No |
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