Answer / vignesh1988i

A SMALL IMPLEMENTATION OF POINTERS

#include<stdio.h>
#include<conio.h>
void main()
{
int n,*p,*q;
printf("enter the number of lines :");
scanf("%d",&n);
for(int i=1,p=&i;*p<=n;*p++)
{
printf("\n");
for(int j=1,q=&j;*q<=*p;*q++)
{
printf("%d",*p);
printf(" ");
}
}
getch();
}

Answer / manvi

main()
{
int i,j,n;
printf("enter the limit");
scanf("%d",&n);
for(i=1;i<=n;i++)
{

for(j=0;j<i;j++)
{
printf("%d",i);
}
printf("\n");
}

}

Answer / k

#include<iostream.h>
int main()
{int i,j,k;
for(i=1;i<=3;i++)
{cout<<"\n";
for(j=1;j<=3-i;j++)
cout<<" ";
for(k=i;k>0;k--)
cout<<i<<" ";
}
return 0;
}

Answer / rajesh kamar s

void main()

{
int n,i,j;
printf("enter the num of rows\t:");
scanf("%d",&n);

for(i=1;i<=n;i++)
{
for(int k=0;k<n-i;k++)
printf(" ");
for(j=1;j<=i;j++)
printf("%d ",i);
printf("\n");
}
}

Write one statement equalent to the following two statements x=sqr(a); return(x); Choose from one of the alternatives a.return(sqr(a)); b.printf("sqr(a)"); c.return(a*a*a); d.printf("%d",sqr(a));

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