What is the output of printf("%d")?
Answers were Sorted based on User's Feedback
Answer / arnab kuamr mahapatra
it will print a garbage value
that means default value an integer
Is This Answer Correct ? | 1 Yes | 0 No |
Answer / ashif ali
it will display only garbage value because
int a=12;
printf("%d");
output=12
Is This Answer Correct ? | 8 Yes | 8 No |
Answer / saranya
IT will print a warning only. So the output will be some
garbage value.
Is This Answer Correct ? | 1 Yes | 1 No |
Answer / beloshe vinod
Output will depends on number of values(local variables)
pushed onto stack .Out of that top of stack will gets printed
e.g.
static int a=89;
int b=67;
printf("%d");
will result in :> 67
Is This Answer Correct ? | 2 Yes | 2 No |
Answer / vijay kumar cet bikaner 1st y
the output of printf("%d") is 0 beacause machine dureng the
execution of program has no address in the memory location
then it goes to the starting point then it print out the
value 0 .....
Is This Answer Correct ? | 1 Yes | 1 No |
Answer / vinod
It prints the value in the stack.That means the if there is
previous initialisation of values.If there are no
definitions of integer varaibles,it would display the
garbage value.
Is This Answer Correct ? | 1 Yes | 1 No |
Answer / sonu
The Output is 0.rite now run and check answer. thats right
answer.
Is This Answer Correct ? | 0 Yes | 0 No |
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