write a program that takes 5 digit no and calculate 2 power
that no and print it.
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Answer / venkataramakrishna.danduri
#include <iostream.h>
void main()
{
int b = 0;
int num5digit;
cin>>num5digit;
b = 1<< num5digit;
cout<<"b = "<<b;
}
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / kathir
#include<iostream.h>
void main()
{
int a,n=0;
cout<<"Enter the 5 didgit no:"<<endl;
cin>>a;
n=(a*a);
cout<<"The two power given no is:"<<n<<endl;
}
| Is This Answer Correct ? | 4 Yes | 6 No |
Answer / yeah
#include<iostream.h>
#include<math.h>
void main()
{
int a,n=1,i;
cout<<"enter Num";
cin>>a;
//n=pow(2,a);
for(i=0;i<a;i++)
n*=2;
cout<<n;
}
| Is This Answer Correct ? | 3 Yes | 6 No |
Given the following seqment of code containing a group of nested if instructions: y = 9; if ((x==3) || (x == 5)) y++; else if (x == 2) y *= 2; else if (x == 4 ) y-= 7; else y = 8; Enter a segment of code (without any IF statements) that does exectly the same thing using the switch structure.
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