Texas PLACEMENT PAPERS ------- Placement Paper-2

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Texas PLACEMENT PAPERS ------- Placement Paper-2..

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>^M
> THIS IS TI jadavpur for ECE students.for cs
another paper is ^M
>given^M
>^M
>1.two transistors are connected Vbe is 0.7volts .this is
simple ckt.one ^M
>transistor is diode equivalent. & asked the o/p across the
2 nd transistor.^M
>2.simple k map ans is Bbar.^M
>3.^M
>^M
> Emitter^M
>---R-------transistorbase| --^M
> | ---^M
> collector^M
> in above capacitor is connected parallel with
resistance ^M
>r.capacitor is not shown^M
> in fig.capacitor is used for in this ckt:^M
>^M
>^M
> ans:a.speedupb.active bypass c.decoupling^M
> 4.^M
>^M
> -----R------I----------o/p^M
> |___R____ |^M
> in above r is resistence.I is
cmos inverter.^M
> then ckt is used for:^M
>^M
>^M
> a.schmitt trigger b.latch
c.inverter ^M
>d.amplifier^M
>^M
>^M
> 5.simple amplifier ckt openloop gain of amplifier
is 4.V in ^M
>=1v.asked for V x?^M
> amplifdier + is connected to base. - is connected to
i/p in between ^M
>5k is connected.^M
> from o/p feedback connected to - of amplifier with
15k.this is ckt.^M
>^M
>^M
> 6.resistence inductot cap are serially connected to
ac voltage 5 ^M
>volts.voltage across^M
> inductor is given.R I C values are given & asked
for^M
> voltages across resistence & capacitor.^M
> 7.^M
> ___ R_____^M
> | |^M
> ---R------OPAMP ----------^M

> |---^M
> R1 R1 is for wjhat i mean what is the
purpose of R1.^M
> |^M
>^M
> ground^M
>^M
>^M
> 8.asked for Vo at the o/p.it is like simple cmos
realization that is n ^M
>block is above^M
> & p block is below.Vdd is 3 volts at supply.V
threshold 5 volts.^M
> 9.2 d ffs are connected in asyncro manner .clock 10
MEGAHZ.gate delay ^M
>is 1 nanosec.^M
> A B are the two given D FFs.asked for AB output is:^M
>^M
>^M
> a.updown^M
> b.up c. updown glitching like that (take care abt
glitching word)^M
>^M
> 10.^M
>^M
>^M
> ----------------| subtractor|---------o/p^M
> |___HPF____|^M

>^M
> the ckt is LPF ,HPF or APF ?^M
>^M
> 11.in a queue at the no of elements removed is
proportional to no of ^M
>elements in^M
> the queue.then no of elements in the queue:^M
> a.increases decreases exp or linearly(so these are the
4 options given ^M
>choose 1 option)^M
> 12.with 2 i/p AND gates u have to form a 8 i/p AND
gate.which is the ^M
>fastest in the^M
> following implementations.^M
> ans we think ((AB)(CD))((EF)(GH))^M

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> 13.with howmany 2:1 MUX u can for 8:1 MUX.answer is
7.^M
> 14. there are n states then ffs used are log n.^M
> 15.cube each side has r units resistence then the
resistence across ^M
>diagonal of cube.^M
> 16.op amp connections asked for o/p^M
> the answer is (1+1/n)(v2-v1).check it out.practise this
type of model.^M
> 17.^M
> _____________ supply^M
> ---|__ ___|^M
> Ii >________ |___ Tranistot^M
> > _______Vo^M
> > _______Vo^M
> |^M
> |^M
> R |^M
> | | Io^M
> ground.^M
>^M
>^M
>^M
>^M
> asked for Io/Ii=? transistor gain is beta.^M
>^M
>^M
> a.(1+beta)square b.1+beta c. beta^M
>^M
>^M
> 18.y=kxsquare. this is transfer function of a block
with i/p x & o/p ^M
>y.if i/p is^M
> sum of a & b then o/p is :--^M
>^M
> a. AM b.FM c. PM^M
> 19.^M
> ------MULTIPLIER--- |^M

>
| |^M
> _____R__|__OPAMP______________________Vo^M
> ---^M
> |^M
> ground.^M
> v in = -Ez then o/p Vo =?^M
> answer is squareroot of -Ez.multiplier
i/ps are a & b then ^M
>its o/p^M
> is a.b;^M

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