Answer / nitin kumar

Steps for 1. Using a SqlConnection
// Fully Commented Code
using System;
using System.Data;
using System.Data.SqlClient;

class SqlConnectionDemo
{
static void Main()
{
// 1. Instantiate the connection
SqlConnection conn = new SqlConnection(
"Data Source=(local);Initial
Catalog=Northwind;Integrated Security=SSPI");

SqlDataReader rdr = null;

try
{
// 2. Open the connection
conn.Open();

// 3. Pass the connection to a command object
SqlCommand cmd = new SqlCommand("select * from
Customers", conn);

//
// 4. Use the connection
//

// get query results
rdr = cmd.ExecuteReader();

// print the CustomerID of each record
while (rdr.Read())
{
Console.WriteLine(rdr[0]);
}
}
finally
{
// close the reader
if (rdr != null)
{
rdr.Close();
}

// 5. Close the connection
if (conn != null)
{
conn.Close();
}
}
}
}

Answer / bhagwat prasad sharma

Steps: SqlConnection with vb.net code
'' Code

imports system.data.sqlclients
Public Class Form1 Inherits System.Windows.Forms.Form
'' createconnection with database

dim con as new sqlconnection("server=bps; database=company; user id=sa; password=admin")

private sub button1_click()

dim str as string="insert into employee (roll_no,name,class) values(@roll_no,@name,@class)"

dim cmd as new sqlcommand =(str,con)

if con.state=connectionstate.closed than
con.open()
'' parameter passing

cmd.parameters.add("@roll_no",type.int)
cmd.parameters.add("@name",type.varchar)
cmd.parameters.add("@class",type.varchar)

cmd.parameters("@roll_no").value= txtroll.text
cmd.parameters("@name").value=txtname.text
cmd.parameters("@class").value= txtclass.text

dim i as integer
i=cmd.executeNonquery

if i>o
msgbox("addition successful")
else
msgbox("sum mistakes into add")
end if
' end of connection
con.close()
end sub
end class

When would you not use the oleDbConnection object? a) To connect to an SQL 7.0 database. b) To connect to a DB/2 database. c) To connect to an Access database. d) To connect to an SQL 6.5 database.

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