Answer / pavan_mustyala

In C-Language, In general, we compare each element of the
array in a loop that iterates till the element is found.
This is called Linear search.

while(1)
{
// code here
if(element found)
break;
}

Here, execution time depends on the array size and position
of the element in the array.
For sorted arrays, we can use techniques such as binary
search using which execution is faster.

Answer / palanisaran

my $element = 'Whatever you are searching for' ;
if (grep {$_ eq $element} @TheArray) {
print "Element '$element' found!\n" ;
}

main() { int c[ ]={2.8,3.4,4,6.7,5}; int j,*p=c,*q=c; for(j=0;j<5;j++) { printf(" %d ",*c); ++q; } for(j=0;j<5;j++){ printf(" %d ",*p); ++p; } }

1 Answers  

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struct Foo { char *pName; }; main() { struct Foo *obj = malloc(sizeof(struct Foo)); clrscr(); strcpy(obj->pName,"Your Name"); printf("%s", obj->pName); } a. Your Name b. compile error c. Name d. Runtime error

3 Answers   HCL,

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How do you verify if the two sentences/phrases input is an anagram using predefined functions in string.h and by using arrays?

0 Answers  

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main() { char *a = "Hello "; char *b = "World"; clrscr(); printf("%s", strcat(a,b)); } a. Hello b. Hello World c. HelloWorld d. None of the above

3 Answers   HCL,

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There is a lucky draw held every day. if there is a winning number eg 1876,then all possible numbers like 1867,1687,1768 etc are the numbers that match irrespective of the position of the digit. Thus all these numbers qualify fr the lucky draw prize Assume there is no zero digit in any numbers. write a program to show all the possible winning numbers if a "winning number"is passed as an arguments to the function.

1 Answers   Nagarro,

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How will you print % character? a. printf(“\%”) b. printf(“\\%”) c. printf(“%%”) d. printf(“\%%”)

4 Answers   HCL,

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how to delete an element in an array

2 Answers   IBM,

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main(){ int a= 0;int b = 20;char x =1;char y =10; if(a,b,x,y) printf("hello"); }

1 Answers   TCS,

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main() { char *p="GOOD"; char a[ ]="GOOD"; printf("\n sizeof(p) = %d, sizeof(*p) = %d, strlen(p) = %d", sizeof(p), sizeof(*p), strlen(p)); printf("\n sizeof(a) = %d, strlen(a) = %d", sizeof(a), strlen(a)); }

1 Answers  

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int i=10; main() { extern int i; { int i=20; { const volatile unsigned i=30; printf("%d",i); } printf("%d",i); } printf("%d",i); }

1 Answers  

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main() { extern int i; { int i=20; { const volatile unsigned i=30; printf("%d",i); } printf("%d",i); } printf("%d",i); } int i;

1 Answers  

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main( ) { int a[2][3][2] = {{{2,4},{7,8},{3,4}},{{2,2},{2,3},{3,4}}}; printf(“%u %u %u %d \n”,a,*a,**a,***a); printf(“%u %u %u %d \n”,a+1,*a+1,**a+1,***a+1); }

2 Answers  

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