Hi, Anybody could tell me What is the 3rd Largest Number in
the series..Thanks in Advance..
Answers were Sorted based on User's Feedback
Answer / saket bharti
a=Array(-1,0,23,-12,98,-300)
Dim temp,i,j
For j=0 to UBound(a)-1
For i=0 to UBound(a)-1
If a(i)<a(i+1) then
temp=a(i+1)
a(i+1)=a(i)
a(i)=temp
End If
Next
Next
Msgbox a(2)
| Is This Answer Correct ? | 4 Yes | 1 No |
a=array(1,22,3,40,12)
For i=0 to ubound(a)
For j=0 to ubound(a)
If a(i)>a(j) then
temp=a(i)
a(i)=a(j)
a(j)=temp
end if
Next
Next
print a(2)
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / anwar basha
dim temp,i,j
a=array(5,3,7,9,2,...)
for i=0 to ubound(a)-1
for j=i+1 to ubound(a)
if a(i)>a(j) then
temp=a(i)
a(i)=a(j)
a(j)=temp
end if
next
next
k=ubound(a)-2
msgbox a(k)
| Is This Answer Correct ? | 0 Yes | 0 No |
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