Hi, Anybody could tell me What is the 3rd Largest Number in
the series..Thanks in Advance..

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Hi, Anybody could tell me What is the 3rd Largest Number in the series..Thanks in Advance....

Answer / saket bharti

a=Array(-1,0,23,-12,98,-300)

Dim temp,i,j

For j=0 to UBound(a)-1

For i=0 to UBound(a)-1

If a(i)<a(i+1) then

temp=a(i+1)

a(i+1)=a(i)

a(i)=temp

End If

Next

Next

Msgbox a(2)

Is This Answer Correct ?    4 Yes 1 No

Hi, Anybody could tell me What is the 3rd Largest Number in the series..Thanks in Advance....

Answer / pushkar1206

a=array(1,22,3,40,12)
For i=0 to ubound(a)
For j=0 to ubound(a)
If a(i)>a(j) then
temp=a(i)
a(i)=a(j)
a(j)=temp
end if
Next
Next
print a(2)

Is This Answer Correct ?    1 Yes 0 No

Hi, Anybody could tell me What is the 3rd Largest Number in the series..Thanks in Advance....

Answer / anwar basha

dim temp,i,j
a=array(5,3,7,9,2,...)

for i=0 to ubound(a)-1
for j=i+1 to ubound(a)
if a(i)>a(j) then
temp=a(i)
a(i)=a(j)
a(j)=temp
end if
next
next
k=ubound(a)-2
msgbox a(k)

Is This Answer Correct ?    0 Yes 0 No

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