1.write a program in C# to find a given point which is inside in a circle. Giv

1.write a program in C# to find a given point which is
inside in a circle. Given circle's radius and its center
point?
2.Write a program in C# to generated 20 prime numbers
greater than a given number? (It should be more efficient
for large numbers also)
3. Write a Code to check whether a given point is inside a
circle or not? given Circle's raduis and its center point.
4. using oops concept, design an elevator do not forget
buttons on each floor..

Question Posted / saranyabalaraman

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1.write a program in C# to find a given point which is inside in a circle. Given circle's rad..

Answer / chandra kiran

answer for 3rd question
static void Main(string[] args)
{
Console.Write("Please Enter the radius of the circle : ");
int r = Convert.ToInt32(Console.ReadLine());
Console.WriteLine("Please Enter the center of the circle ");
Console.Write("Please Enter x coordinate of the centre : ");
int x1 = Convert.ToInt32(Console.ReadLine());
Console.Write("Please Enter y coordinate of the centre : ");
int y1 = Convert.ToInt32(Console.ReadLine());
Console.WriteLine("Please Enter the Point ");
Console.Write("Please Enter x coordinate of the point : ");
int x2 = Convert.ToInt32(Console.ReadLine());
Console.Write("Please Enter y coordinate of the point : ");
int y2 = Convert.ToInt32(Console.ReadLine());
int check =Convert.ToInt32(Math.Sqrt(Math.Pow(x2-x1,2)+Math.Pow(y2-y1,2)));
if (check < r)
Console.WriteLine("Inside the Circle");
else if (check == r)
Console.WriteLine("On the Circle");
else
Console.WriteLine("Outside the Circle");
}
//don't enter centre of the circle and point (1,2) ,(5,6) like this enter each coordinate individually

Is This Answer Correct ?

8 Yes

2 No

1.write a program in C# to find a given point which is inside in a circle. Given circle's rad..

Answer / ganesh

take 4 textboxes , cx=centre x, cy=centre y, r=radius,
x=x co-oridnate, y=y co-ordinate.
double d;

calculate the distnace between centre and point taken
if distance less than radius(inside) else outside

simple

d = Math.Sqrt(Math.Pow((int.Parse(cx.Text) - int.Parse(x.Text)), 2) + Math.Pow((int.Parse(cy.Text) - int.Parse(y.Text)), 2));

if (d <Double.Parse( r.Text))
Label1.Text = "inside";
else
Label1.Text = "outside";

Is This Answer Correct ?

5 Yes

1 No

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