Answer / muavia

#include<stdio.h>
#include<conio.h>
void main(void)
{
printf("Which table you want: ");
int t;
scanf("%d",&t);

for (int i=1;i<11;i++)
printf("\n%d * %d = %d",t,i,t*i);
getch();
}

Answer / amit kumar singh

#include<stdio.h>
#include<conio.h>
void main()
int i;
printf("the table of two no");

for(i=1;i<=10;i++)
{
printf("
%d",r*2);
getch();
}

Answer / chandan partap singh

#include<stdio.h>
#include<conio.h>
void main()
{
int i,c;
clrscr();
printf("Table of 2

");
for(i=1;i<=10;i++)
{
printf("2*%d=%d

",i,2*i);
}
getch();

}

Answer / sandeep tayal

If you are looking for printing a table using c in unix
environment where c is actually used you can find the
following link helpful.

http://myblogs.netne.net/program-to-print-table-of-2-in-c-using-vi/

Give a very good method to count the number of ones in a 32 bit number. (caution: looping through testing each bit is not a solution)

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main() { printf("%d", out); } int out=100;

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why the range of an unsigned integer is double almost than the signed integer.

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