#define CUBE(x) (x*x*x) main() { int a,b=3; a=cube(b++); printf("%d %d&

#define CUBE(x) (x*x*x)
main()
{ int a,b=3;
a=cube(b++);
printf("%d %d",a,b);
}
What should be the value of a and b? My calc a=4 but syst
a=6 how pls tell me if you know it?

Question Posted / b.sudharsan

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#define CUBE(x) (x*x*x) main() { int a,b=3; a=cube(b++); printf("%d %d",a,b); } Wh..

Answer / vignesh1988i

surely 'a' cannot be 4 or 6.... it will be the value of b... since we are multiplying b++ thrice...... so surely 'a' cannot be 4 or 6.....

according to me b=6 , and a=60......

thank u

Is This Answer Correct ?

4 Yes

9 No

#define CUBE(x) (x*x*x) main() { int a,b=3; a=cube(b++); printf("%d %d",a,b); } Wh..

Answer / jesaul

The code will not compile. The macro is in wrong case.
After fixing that you would get 27 6

Is This Answer Correct ?

2 Yes

7 No

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