If second no is twice the first no and first no is thrice
the third no.Their avg is 20.Find the greatest no?
Answer Posted / risha ramanathan
let 1st number be x
thus 2nd number is 2x
let 3rd number be y
since 1st number is thrice the 3rd number, thus
x= 3y
now : 1st no = 3y
2nd no = 6y
3rd no = y
so, (3y+6y+y)/3=20
y = 6
since 2nd no is 6y, therefore 6y = 36
so the 2nd number is the greatest :D
Is This Answer Correct ? | 22 Yes | 3 No |
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