Answer Posted / srujana

we can access the command-line arguments by passing the
arguments argv and argc on to the main() function where
argv represents an array of pointers to strings and argc
holds the int value which is equal to the number of strings
that are in argv

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658

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706

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#include int main(){ int i=10; int *ptr=&i; *ptr=(int *)20; printf("%d",i); return 0; } Output: 20 can anyone explain how came the output is 20

1358

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629

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