How do I access command-line arguments?
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Answer / srujana
we can access the command-line arguments by passing the
arguments argv and argc on to the main() function where
argv represents an array of pointers to strings and argc
holds the int value which is equal to the number of strings
that are in argv
Is This Answer Correct ? | 10 Yes | 1 No |
Answer / reejusri
In order to access the command arguments, the main()
function must have a prototype similar to the following.
int main(int argc, char * argv[])
The names argc and argv are usually used for the
parameters, but a programmer could use different names.
Is This Answer Correct ? | 6 Yes | 4 No |
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Write a program to replace n bits from the position p of the bit representation of an inputted character x with the one's complement. Method invertBit takes 3 parameters x as input character, p as position and n as the number of positions from p. Replace n bits from pth position in 8 bit character x. Then return the characters by inverting the bits.
how to exchnage bits in a byte b7<-->b0 b6<-->b1 b5<-->b2 b4<-->b3 please mail me the code if any one know to rajeshmb4u@gmail.com
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