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How do I access command-line arguments?
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Answer / srujana
we can access the command-line arguments by passing the
arguments argv and argc on to the main() function where
argv represents an array of pointers to strings and argc
holds the int value which is equal to the number of strings
that are in argv
| Is This Answer Correct ? | 10 Yes | 1 No |
Answer / reejusri
In order to access the command arguments, the main()
function must have a prototype similar to the following.
int main(int argc, char * argv[])
The names argc and argv are usually used for the
parameters, but a programmer could use different names.
| Is This Answer Correct ? | 6 Yes | 4 No |
6)What would be the output? main() { int u=1,v=3; pf("%d%d",u,v); funct1(&u,&v); pf("%d%d\n",u,v); } void funct1(int *pu, int *pv) { *pu=0; *pv=0; return; } a)1 3 1 3 b)1 3 1 1 c)1 3 0 0 d)1 1 1 1 e) 3 1 3 1
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