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Suppose there are two vessels. One of diameter = D and
other vessel dia = d. Suppose in vessel with dia D, water
is filled upto height H and vessel with dia d is empty. Now
both vessels are connected.Water will flow from D dia vesel
to small d dia vessel.Suppose after equilibrium height of
water in vessel with dia D is h. How much is h in terms of
D, d,H etc?
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Answer Posted / shivaray
After connecting each other in both vessels volumes are
remane same.
After equilibrium height for dia D is 'h' that means volume
is v1=Pi/4 *D^2*h
After equilibrium height for dia d is 'H-h' that means
volume is v2=Pi/4 *d^2*(H-h)
v1=v2
i.e D^2*h=d^2*(H-h)
(D^2+d^2)*h=d^2*H
so ans is h= d^2*H/(d^2+D^2)
I am requesting to Mr.Banke Bihari & Mr.Jikku Joseph to
make a comment on this answer.Bcz their ans is not correct
| Is This Answer Correct ? | 3 Yes | 8 No |
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