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In a club there are certain no. of males and females. If 15 females are absent then no. of males will be twice that of females. If 45 males are absent then female strength will be 5 times that of males. Find no. of males actually present.
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Answer Posted / Sudhakar Tripathi
Let the number of males be M and the number of females be F. We know two things: (1) When 15 females are absent, M = 2Fn(2) When 45 males are absent, F = 5M.nNow let's solve for F when all members are present, then set up an equation to find M:nWhen all females are present, F = 45 - 15 = 30nSo when all males and females are present: M + F = 45nUsing the relationships we know, we can rewrite this as M + (2F) = 45 and F = 5M.nBy substituting F in the first equation, we get: M + (10M) = 45 => 11M = 35 => M = 3.18.nSince the number of males must be an integer, this question does not have a valid solution according to the provided conditions.
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