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Answer Posted / darcl facility
Suppose A gensets is 500 Kva and load is running 50 % on the Gen Sets.
Now We can Canclulate the following-
Max Load will be- 500*1.39= 695
50 % Load will be= 685*.5= 347 A.
Now Calculate the Kwh = 1.732*415*347*.8= 200 Unit Appx per Hours.
As we know the Average maximum UPL is 3.4 to 3.8 Unit.
Load is apprimate 50 percenatge so Divide the total unit by 3
Results is = 200/3= Apprximate 65 Liter per hours.
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