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Answer Posted / arjun
Ideally, In Saturation region, Ids is independent of Vds.
But the reverse biased junction between the drain and body forms a depletion region of width Ld which increases with Vds(= Vdb).
This increase in the depletion region width will decrease the size of the channel.
L(eff) = L(actual) - Ld.
With the increase in Vds, The effective channel length decreases which means higher current.
This is important because it reduces the gain of the amplifier
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