Answer Posted / munna kumar das

suppose concrete mix ratio=1:1.5:3
and dry material required for 1cum of concrete =1.54
Let 1x+1.5x+3x=1.54
x=0.28
cement=0.28*1=0.28cum=0.28*1440/50=8.06bags

sand=0.28*1.5=0.42cum=0.42*1500=630Kg
coarse agg=0.28*3=0.84cum=0.84*1550=1302kg
add 6 to 8% extra material.
This process very easy to understand.

I need model question papers for writing the Dubai municipality exam,for G+1

10659

---

What is the exception critarea of cube?

2576

---

How to calculate concrete in percentage wise ,for example cement 18% sand 40% aggregate 40% and Stell 2% ,I need and??

2155

---

What should be the lap length in raft if height of raft is 0.800mm ...it couldn't b 50D or 40D...we just have to join upper and bottom reinforced...is there any formula for determine it...

2022

---

What is the minimum size of the particles of silt soil?

1432

---

How can you produce desired alloys and discuss their applications in daily life.

1285

---

What is meant by a context menu in a cad software?

1156

---

give me the mix proportion for design mix concrete M 7.5 grade 1:4:8

4080

---

Why should you consider yourself fit to be hired by jindal steel.

4486

---

need to join coaching institute in coimbatore tamilnadu ......say me the best coaching for IAS

1930

---

What is labor and material payment bond?

1202

---

what is the mix design for M:60 with micro silica andmetakaoline?

2298

---

Explain the term 'Gross unit rate' and identify the items that may be included in the gross unit rate.

11687

---

Bernaullis theorem deals with the law of conservation of mass momentum energy none

2064

---

Which are the Steel tests ?

1284

---